MacBookPro.lan 2025-6-22:13:31:34
This commit is contained in:
5
.obsidian/community-plugins.json
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5
.obsidian/community-plugins.json
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@@ -14,7 +14,8 @@
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"obsidian-git",
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"wikilinks-to-mdlinks-obsidian",
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"obsidian-daily-note-outline",
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"mysnippets-plugin",
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"github-sync",
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"extended-graph"
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"contribution-graph",
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"obsidian-tasks-plugin",
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"quickadd"
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]
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.obsidian/graph.json
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.obsidian/graph.json
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@@ -1,6 +1,6 @@
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{
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"collapse-filter": false,
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"search": "tag:#s/maths/analyse/complexes ",
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"search": "",
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"showTags": false,
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"showAttachments": false,
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"hideUnresolved": false,
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@@ -130,6 +130,6 @@
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"repelStrength": 8.4228515625,
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"linkStrength": 1,
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"linkDistance": 30,
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"scale": 0.33028687809066476,
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"close": false
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"scale": 0.05130349568508325,
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"close": true
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}
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.obsidian/plugins/contribution-graph/main.js
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.obsidian/plugins/contribution-graph/main.js
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.obsidian/plugins/contribution-graph/manifest.json
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.obsidian/plugins/contribution-graph/manifest.json
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{
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"id": "contribution-graph",
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"name": "Contribution Graph",
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"version": "0.10.0",
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"minAppVersion": "1.3.0",
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"description": "Generate a interactive heatmap graph to visualize and track your productivity",
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"author": "vran",
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"authorUrl": "https://github.com/vran-dev",
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"isDesktopOnly": false,
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"fundingUrl": "https://www.buymeacoffee.com/vran"
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}
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1
.obsidian/plugins/contribution-graph/styles.css
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.obsidian/plugins/contribution-graph/styles.css
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.obsidian/plugins/extended-graph/data.json
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2
.obsidian/plugins/extended-graph/data.json
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@@ -195,7 +195,7 @@
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"repelStrength": 8.4228515625,
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"linkStrength": 1,
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"linkDistance": 30,
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"scale": 0.33028687809066476,
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"scale": 1.2190307421143933,
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"close": false
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},
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"states": [
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21
Untitled.md
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Untitled.md
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---
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aliases:
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tags:
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up:
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---
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# EXERCICE 1 (6 points )
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(Commun à tous les candidats)
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## Partie A
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On considère la fonction $f$ définie sur l’ensemble $\mathbb{R}$ des nombres réels par :
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$f (x) = \frac{7}{2} - \frac{1}{2}(e^{ x } - e^{ -x })$
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### 1)
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#### a) Déterminer la limite de la fonction $f$ en $+\infty$
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On a :
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$\begin{align} \lim\limits_{ x \to \infty } f(x) &= \lim\limits_{ x \to \infty } \left( \frac{7}{2} - \frac{1}{2}(e^{ x } - e^{ -x }) \right) \\&= \frac{7}{2} - \frac{1}{2}\lim\limits_{ x \to \infty } e^{ ^{x} } - e^{ -x } \\&= \frac{7}{2} - \infty \\&= -\infty\end{align}$
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#### b) Montrer que la fonction $f$ est strictement décroissante sur l’intervalle $[0 ; +∞[$
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On sait que $x \mapsto e^{ x }$ est croissante sur cet intervalle, et supérieure à 1
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#### c) Montrer que l’équation $f (x) = 0$ admet, sur l’intervalle $[0 ; +∞[$, une unique solution, que l’on note $\alpha$.
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### 2) En remarquant que, pour tout réel $x$, $f (−x) = f (x)$, justifier que l’équation $f (x) = 0$ admet exactement deux solutions dans $\mathbb{R}$ et qu’elles sont opposées
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daily/2025-06-22.md
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daily/2025-06-22.md
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# Todo
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# I did
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> [!smallquery]- Modified files
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> ```dataview
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> LIST file.mtime
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> where file.mtime > date(this.file.name) and file.mtime < (date(this.file.name) + dur(1 day)) sort file.mtime asc
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> ```
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```tasks
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done 2025-06-22
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short mode
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```
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# I am gratefull to
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