MacBookPro.lan 2026-5-1:3:47:38
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@@ -298,8 +298,10 @@ header-auto-numbering:
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> > - $2\cdot 111312211312111312\cdot \overbracket{311}^{\mathclap{[3^{1}X^{\neq 3}}}2112\cdot \overbracket{3\cdot \underbracket{22}_{\mathclap{[2^{2}1^{3}]}}}^{\mathclap{[3^{1}X^{\neq 3}}} 1112\cdot \overbracket{13}^{\mathclap{[1^{1}X^{1}}}211322211312113211$
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> > - $2\cdot \overbracket{311}^{\mathclap{[3^{1}X^{\neq 3}}}3112221131112\cdot \overbracket{311}^{\mathclap{[3^{1}X^{\neq 3}}}31112\cdot \overbracket{13}^{\mathclap{[1^{1}X^{1}}}21122112\cdot \overbracket{13}^{\mathclap{[1^{1}X^{1}}}22\cdot \overbracket{311}^{\mathclap{[3^{1}X^{\neq_3}}}2\cdot \overbracket{\color{#FCD600}111}^{[1^{3}}\color{#FCD600}3122113322113111221131221$
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> > - 23113112221131112311311121321122112132231121113122113322113111221131221
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> > - 213211321322113311 21321133112111312212221121113221321123113112221232221133122211113112211
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> > - $2\cdot 1321132\cdot \overbracket{13}^{\mathclap{[1^{1}X^{1}}}221133112\cdot \overbracket{13}^{\mathclap{[1^{1}X^{1}}}21133112\cdot \overbracket{111}^{[1^{3}}31221222112\cdot \overbracket{111}^{[1^{3}}3\cdot \overbracket{2213}^{\mathclap{[2^{2}1^{1}X^{1}}}2112\cdot \overbracket{311}^{\mathclap{[3^{1}X^{\neq 3}}}311222\cdot \overbracket{12}32221133122211113112211$
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> > - $2\cdot 1321132\cdot \overbracket{13}^{\mathclap{[1^{1}X^{1}}}221133112\cdot \overbracket{13}^{\mathclap{[1^{1}X^{1}}}21133112\cdot \overbracket{111}^{[1^{3}}31221222112\cdot \overbracket{111}^{[1^{3}}3\cdot \overbracket{2213}^{\mathclap{[2^{2}1^{1}X^{1}}}2112\cdot \overbracket{311}^{\mathclap{[3^{1}X^{\neq 3}}}311222\cdot \overbracket{12}^{[1^{1}X^{1}}322211331222113112211$
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> > - 213211321322113311 213211331121113122122211211132213211231131122212322211331222113112211
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> > - 2111312211312111322212322121113122123211231131122113221123113221113122112132113213211121332212311322113212221
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> > - 2111312211312111322212321121113122123211231131122113221123113221113122112132113213211121332212311322113212221
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> >
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> >
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> > Ce qui montre bien que toute chaîne qui termine par $1$ finit par atteindre le cycle $(1)$.
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