eduroam-prg-hf-1-5-62.net.univ-paris-diderot.fr 2025-9-29:13:20:41
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@@ -1,34 +1,32 @@
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---
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description: |
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```python
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from collections import defaultdict
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from pprint import pprint
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tree = lambda: defaultdict(tree) # arbre = dictionnaire contenant un arbre
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example = tree() # création de l'arbre
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example["A"]["A.1"]
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example["A"]["A.2"]["A.2.1"]
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example["B"]["B.1"]
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def tree_to_dicts(tree): # transformer en vrai dictionnaire
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return {key: tree_to_dicts(tree[key]) for key in tree}
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pprint(tree_to_dicts(example))
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def add_path(tree, path):
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for node in path:
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tree = tree[node]
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add_path(example, ["B", "B.2", "B.2.1"])
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add_path(example, "B>B.2>B.2.2".split(">"))
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pprint(tree_to_dicts(example))
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```
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up: [[python tips]]
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link: "https://gist.github.com/hrldcpr/2012250"
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author: [[harold cooper]]
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tags:
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- "#s/informatique/langage/python"
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---
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up::[[python tips]]
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link::https://gist.github.com/hrldcpr/2012250
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author::[[harold cooper]]
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title::"definir des [[structure de données.arbre|arbres]] avec les defaultdicts du module [[python module collections]]"
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#s/informatique/langage/python
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----
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Permet de définir la structure d'[[structure de données.arbre]] de manière simple, grace aux `defaultdicts` (module collections)
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# Résumé
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```python
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from collections import defaultdict
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from pprint import pprint
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tree = lambda: defaultdict(tree) # arbre = dictionnaire contenant un arbre
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example = tree() # création de l'arbre
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example["A"]["A.1"]
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example["A"]["A.2"]["A.2.1"]
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example["B"]["B.1"]
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def tree_to_dicts(tree): # transformer en vrai dictionnaire
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return {key: tree_to_dicts(tree[key]) for key in tree}
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pprint(tree_to_dicts(example))
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def add_path(tree, path):
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for node in path:
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tree = tree[node]
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add_path(example, ["B", "B.2", "B.2.1"])
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add_path(example, "B>B.2>B.2.2".split(">"))
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pprint(tree_to_dicts(example))
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```
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# Définition
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```python
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