MacBookPro.lan 2026-5-1:2:48:21
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@@ -299,7 +299,7 @@ header-auto-numbering:
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> > - $2\cdot \overbracket{311}^{\mathclap{[3^{1}X^{\neq 3}}}3112221131112\cdot \overbracket{311}^{\mathclap{[3^{1}X^{\neq 3}}}31112\cdot \overbracket{13}^{\mathclap{[1^{1}X^{1}}}21122112\cdot \overbracket{13}^{\mathclap{[1^{1}X^{1}}}22\cdot \overbracket{311}^{\mathclap{[3^{1}X^{\neq_3}}}2\cdot \overbracket{\color{#FCD600}111}^{[1^{3}}\color{#FCD600}3122113322113111221131221$
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> > - $2\cdot \overbracket{311}^{\mathclap{[3^{1}X^{\neq 3}}}3112221131112\cdot \overbracket{311}^{\mathclap{[3^{1}X^{\neq 3}}}31112\cdot \overbracket{13}^{\mathclap{[1^{1}X^{1}}}21122112\cdot \overbracket{13}^{\mathclap{[1^{1}X^{1}}}22\cdot \overbracket{311}^{\mathclap{[3^{1}X^{\neq_3}}}2\cdot \overbracket{\color{#FCD600}111}^{[1^{3}}\color{#FCD600}3122113322113111221131221$
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> > - 23113112221131112311311121321122112132231121113122113322113111221131221
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> > - 23113112221131112311311121321122112132231121113122113322113111221131221
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> > - 213211321322113311 21321133112111312212221121113221321123113112221232221133122211113112211
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> > - 213211321322113311 21321133112111312212221121113221321123113112221232221133122211113112211
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> > - $2\cdot 1321132\cdot \overbracket{13}^{\mathclap{[1^{1}X^{1}}}221133112\cdot \overbracket{13}^{\mathclap{[1^{1}X^{1}}}21133112\cdot \overbracket{111}^{[1^{3}}31221222112\cdot \overbracket{111}^{[1^{3}}3\cdot \overbracket{2213}^{\mathclap{[2^{2}1^{1}X^{1}}}2112\cdot \overbracket{311}^{\mathclap{[3^{1}X^{\neq 3}}}311222\cdot \over1232221133122211113112211$
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> > - $2\cdot 1321132\cdot \overbracket{13}^{\mathclap{[1^{1}X^{1}}}221133112\cdot \overbracket{13}^{\mathclap{[1^{1}X^{1}}}21133112\cdot \overbracket{111}^{[1^{3}}31221222112\cdot \overbracket{111}^{[1^{3}}3\cdot \overbracket{2213}^{\mathclap{[2^{2}1^{1}X^{1}}}2112\cdot \overbracket{311}^{\mathclap{[3^{1}X^{\neq 3}}}311222\cdot \overbracket{12}32221133122211113112211$
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> >
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> >
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> >
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> >
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> > Ce qui montre bien que toute chaîne qui termine par $1$ finit par atteindre le cycle $(1)$.
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> > Ce qui montre bien que toute chaîne qui termine par $1$ finit par atteindre le cycle $(1)$.
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