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MacBookPro.lan 2026-5-29:2:4:41

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oskar
2026-05-29 02:04:41 +02:00
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@@ -11,6 +11,6 @@ $$\begin{array}{|r|l|}
\left.\displaystyle\lim_{x\rightarrow+\infty} \dfrac{e^x}{x^\alpha}\right|_{\alpha>0} & +\infty \\\hline \left.\displaystyle\lim_{x\rightarrow+\infty} \dfrac{e^x}{x^\alpha}\right|_{\alpha>0} & +\infty \\\hline
\displaystyle\lim_{x\rightarrow+\infty} & \\\hline \displaystyle\lim_{x\rightarrow+\infty} & \\\hline
\left.\displaystyle\lim_{x\rightarrow+\infty} \dfrac{(\ln (x))^{\alpha}}{x^\beta}\right|_{\beta>0} & 0 \\\hline \left.\displaystyle\lim_{x\rightarrow+\infty} \dfrac{(\ln (x))^{\alpha}}{x^\beta}\right|_{\beta>0} & 0 \\\hline
\disp\lim_{x\rightarrow 0} \dfrac{\sin x}x & 1\\\hline \displaystyle \lim_{x\rightarrow 0} \dfrac{\sin x}x & 1\\\hline
\disp\lim_{x\rightarrow 0} \dfrac{1 - \cos(x)}{x^2} & \dfrac12 \\\hline \displaystyle \lim_{x\rightarrow 0} \dfrac{1 - \cos(x)}{x^2} & \dfrac12 \\\hline
\end{array}$$ \end{array}$$